\n
1<\/p>\n\n\n\n
2<\/p>\n\n\n\n
3<\/p>\n\n\n\n
4<\/p>\n\n\n\n
5<\/p>\n<\/div><\/div>\n\n\n\n
Q. Write a program to print number from 5 to 1.<\/p><\/blockquote>\n\n\n\n
#include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i;\t\nfor(i=5;i>=1;i- -)\n{\ncout<<\u201d\\n\u201d<<i;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/p>\n\n\n\n 5<\/p>\n\n\n\n 4<\/p>\n\n\n\n 3<\/p>\n\n\n\n 2<\/p>\n\n\n\n 1<\/p>\n\n\n\n Q. Write a program to print even number from 1 to 20.<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i;\t\nfor(i=2;i<=20;i+=2)\n{\ncout<<\u201d\\n\u201d<<i;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/strong><\/p>\n\n\n\n \n2<\/p>\n\n\n\n 4<\/p>\n\n\n\n 6<\/p>\n\n\n\n 8<\/p>\n\n\n\n 10<\/p>\n\n\n\n 12<\/p>\n\n\n\n 14<\/p>\n\n\n\n 16<\/p>\n\n\n\n 18<\/p>\n\n\n\n 20<\/p>\n\n\n\n <\/p>\n<\/div><\/div>\n\n\n\n Q. Write a program to print odd number from 1 to 10.<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i;\t\nfor(i=1;i<=10;i+=2)\n{\ncout<<\u201d\\n\u201d<<i;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/strong><\/p>\n\n\n\n \n\n1<\/p>\n\n\n\n 3<\/p>\n\n\n\n 5<\/p>\n\n\n\n 7<\/p>\n\n\n\n 9<\/p>\n<\/div><\/div>\n<\/div><\/div>\n\n\n\n Q. Find output.<\/strong><\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i;\t\nfor(i=5;i<=50;i+=5)\n{\ncout<<\u201d\\n\u201d<<i;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/p>\n\n\n\n \n\n5<\/p>\n\n\n\n 10<\/p>\n\n\n\n 15<\/p>\n\n\n\n 20<\/p>\n\n\n\n 25<\/p>\n\n\n\n 30<\/p>\n\n\n\n 35<\/p>\n\n\n\n 40<\/p>\n\n\n\n 45<\/p>\n\n\n\n 50<\/p>\n<\/div><\/div>\n\n\n\n <\/p>\n<\/div><\/div>\n\n\n\n Q.Find output<\/strong><\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i;\t\nfor(i=50;i>=5;i-=5)\n{\ncout<<\u201d\\n\u201d<<i;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/strong><\/p>\n\n\n\n \n50<\/p>\n\n\n\n 45<\/p>\n\n\n\n 40<\/p>\n\n\n\n 35<\/p>\n\n\n\n 30<\/p>\n\n\n\n 25<\/p>\n\n\n\n 20<\/p>\n\n\n\n 15<\/p>\n\n\n\n 10<\/p>\n\n\n\n 5<\/p>\n<\/div><\/div>\n\n\n\n Q.Write a program to print your name up to specified term.<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint n,i;\t\ncout<<\u201dEnter terms\u201d;\ncin>>n;\nfor(i=1;i<=n;i++)\n{\ncout<<\u201d\\n AIPS ACADEMY\u201d;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/strong><\/p>\n\n\n\n \nEnter terms=4<\/p>\n\n\n\n AIPS ACADEMY<\/p>\n\n\n\n AIPS ACADEMY<\/p>\n\n\n\n AIPS ACADEMY<\/p>\n\n\n\n AIPS ACADEMY<\/p>\n\n\n\n Q.Write a program to print numbers from 1 to specified term<\/p><\/blockquote>\n<\/div><\/div>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint n,i;\t\ncout<<\u201dEnter terms\u201d;\ncin>>n;\nfor(i=1;i<=n;i++)\n{\ncout<<\u201d\\n\u201d<<i;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/strong><\/p>\n\n\n\n \nEnter terms=5<\/p>\n\n\n\n 1<\/p>\n\n\n\n 2<\/p>\n\n\n\n 3<\/p>\n\n\n\n 4<\/p>\n\n\n\n 5<\/p>\n<\/div><\/div>\n\n\n\n Q.Write a program to print numbers from specified term to 1.<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint n,i;\t\ncout<<\u201dEnter terms\u201d;\ncin>>n;\nfor(i=n;i>=1;i--)\n{\ncout<<\u201d\\n\u201d<<i;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/strong><\/p>\n\n\n\n \nEnter terms=5<\/p>\n\n\n\n 5<\/p>\n\n\n\n 4<\/p>\n\n\n\n 3<\/p>\n\n\n\n 2<\/p>\n\n\n\n 1<\/p>\n\n\n\n Q.Write a program to print table of input number.<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint n,i,j;\t\ncout<<\u201dEnter any number=\u201d;\ncin>>n;\nfor(i=1;i<=10;i++)\n{\nj=n*i;\ncout<<\u201d\\n\u201d<<j;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/strong><\/p>\n\n\n\n \nEnter any number =5<\/p>\n\n\n\n 5<\/p>\n\n\n\n 10<\/p>\n\n\n\n 15<\/p>\n\n\n\n 20<\/p>\n\n\n\n 25<\/p>\n\n\n\n 30<\/p>\n\n\n\n 35<\/p>\n\n\n\n 40<\/p>\n\n\n\n 45<\/p>\n\n\n\n 50<\/p>\n\n\n\n Q.Write a program to print table of input number in following format.<\/p> Enter any number=5<\/p> 5*1=5<\/p> 5*2=10<\/p> …………..<\/p> ……………<\/p> 5*10=50<\/p><\/blockquote>\n<\/div><\/div>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint n,i,j;\t\ncout<<\u201dEnter any number=\u201d;\ncin>>n;\nfor(i=1;i<=10;i++)\n{\nj=n*i;\ncout<<\u201d\\n\u201d<<n<<\u201d*\u201d<<i<<\u201d=\u201d<<j;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/strong><\/p>\n\n\n\n \nEnter any number=5<\/p>\n\n\n\n 5*1=5<\/p>\n\n\n\n 5*2=10<\/p>\n\n\n\n …………..<\/p>\n\n\n\n ……………<\/p>\n\n\n\n 5*10=50<\/p>\n\n\n\n Q.Write a program to print Factorial of input number.<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint n,i,j=1;\t\ncout<<\u201dEnter any number=\u201d;\ncin>>n;\nfor(i=n;i>=1;i--)\n{\nj=j*i;\n}\ncout<<\u201dFactorial=\u201d<<j;\ngetch();\n}\n<\/code><\/pre>\n<\/div><\/div>\n<\/div><\/div>\n\n\n\nOutput<\/strong><\/p>\n\n\n\n \nEnter any number=5<\/p>\n\n\n\n Factorial=120<\/p>\n<\/div><\/div>\n\n\n\n OR<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint n,i,j=1;\t\ncout<<\u201dEnter any number=\u201d;\ncin>>n;\nfor(i=n;i>=1;i--)\n{\nj=j*i;\ncout<<i<<\u201d*\u201d;\n}\ncout<<\u201d=\u201d<<j;\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/p>\n\n\n\n \nEnter any number=5<\/p>\n\n\n\n 5*4*3*2*1*=120<\/p>\n<\/div><\/div>\n\n\n\n Q.Write a program to find factor of input number.<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint n,i;\t\ncout<<\u201dEnter any number=\u201d;\ncin>>n;\nfor(i=1;i<=n;i++)\n{\nif(n%i==0)\n{\ncout<<\u201d\\n\u201d<<i;\n}\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/p>\n\n\n\n \nEnter any number =6<\/p>\n\n\n\n 1<\/p>\n\n\n\n 2<\/p>\n\n\n\n 3<\/p>\n\n\n\n 6<\/p>\n<\/div><\/div>\n\n\n\n Q.Write a program to find sum of factors of input number.<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint n,i,s=0;\t\ncout<<\u201dEnter any number=\u201d;\ncin>>n;\nfor(i=1;i<=n;i++)\n{\nif(n%i==0)\n{\ncout<<\u201d\\n\u201d<<i;\ns=s+i;\n}\n}\ncout<<\u201dsum of factor=\u201d<<s;\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/strong><\/p>\n\n\n\n \n\nEnter any number =6<\/p>\n\n\n\n 1<\/p>\n\n\n\n 2<\/p>\n\n\n\n 3<\/p>\n\n\n\n 6<\/p>\n<\/div><\/div>\n\n\n\n sum of factors=12<\/p>\n<\/div><\/div>\n\n\n\n Q.Write a program to check number is perfect or not.<\/p> (sum of factors =two times of number)<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint n,i,s=0;\t\ncout<<\u201dEnter any number=\u201d;\ncin>>n;\nfor(i=1;i<=n;i++)\n{\nif(n%i==0)\n{\ns=s+i;\n}\n}\nif(s==n*2)\ncout<<\u201dPerfect number\u201d;\nelse\ncout<<\u201dNot perfect number\u201d;\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/strong><\/p>\n\n\n\n \nEnter any number=6<\/p>\n\n\n\n Perfect number<\/p>\n\n\n\n Q.Find output.<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i;\t\nfor(i=65;i<=90;i++)\n{\ncout<<\/pre>\n<\/div><\/div>\n\n\n\nOutput<\/strong><\/p>\n\n\n\n 65 66 67 68 69 70 ……..90<\/p>\n\n\n\n Q.Write a program to print uppercase alphabet using ASCII Code.<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i;\t\nfor(i=65;i<=90;i++)\n{\ncout<<(char)i;\n}\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/strong><\/p>\n\n\n\n A B C D E F G H……….Z<\/p>\n\n\n\n Q.Write a program to print uppercase alphabet in reverse order.<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i;\t\nfor(i=90;i>=65;i--)\n{\ncout<<(char)i;\n}\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput <\/p>\n\n\n\n Z Y X W ………………..A<\/p>\n\n\n\n Q. Find Output<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i;\t\nfor(i=90;i>=65;i--)\n{\ncout<<i;\n}\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\n90 89 88 87…..65<\/p>\n\n\n\n Q.Write a program to print lowercase alphabet using ASCII Code.<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i;\t\nfor(i=97;i<=122;i++)\n{\ncout<<(char)i;\n}\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/p>\n\n\n\n a b c d e …………………..z<\/p>\n\n\n\n Q.Find output<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i;\t\nfor(i=97;i<=122;i++)\n{\ncout<<i;\n}\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/p>\n\n\n\n 97 98 99 100…….122<\/p>\n\n\n\n Q.Write a program to print lowercase alphabet in reverse order.<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i;\t\nfor(i=122;i>=97;i--)\n{\ncout<<(char)i;\n}\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/p>\n\n\n\n z y x w ………………..a<\/p>\n\n\n\n Q.Write a program to print numbers from 0 to 9 using ASCII code.<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i;\t\nfor(i=48;i<=57;i++)\n{\ncout<<(char)i;\n}\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/p>\n\n\n\n 0 1 2 3 4 5 6………………..9<\/p>\n\n\n\n Q.Find output.<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i;\t\nfor(i=48;i<=57;i++)\n{\ncout<<i;\n}\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/p>\n\n\n\n 48 49 50 51 52 53 ……..57<\/p>\n\n\n\n Q.Write a program to print following series. <\/p> 1 2 3 4 5 ……………n<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint n,i;\t\ncout<<\u201dEnter value of n=\u201d;\ncin>>n;\nfor(i=1;i<=n;i++)\n{\ncout<<i<<\u201d\\t\u201d;\n}\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput <\/p>\n\n\n\n Enter value of n=5<\/p>\n\n\n\n 1 2 3 4 5 <\/p>\n\n\n\n Q.Write a program to print following series and sum also.<\/p> 1 2 3 4 5 ……………n<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint n,i,s=0;\t\ncout<<\u201dEnter value of n=\u201d;\ncin>>n;\nfor(i=1;i<=n;i++)\n{\ncout<<i<<\u201d\\t\u201d;\ns=s+i;\n}\ncout<<\u201d\\nsum of series=\u201d<<s;\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput <\/p>\n\n\n\n Enter value of n=5<\/p>\n\n\n\n 1 2 3 4 5 <\/p>\n\n\n\n sum of series=15<\/p>\n\n\n\n While loop:-<\/strong><\/h3>\n\n\n\nThis loop is an entry control loop. It executes the block of statement as long as the certain condition is satisfied.<\/p>\n\n\n\n Control exits from loop when the specified condition is false.<\/p>\n\n\n\n Syntax:<\/p>\n\n\n\n \n\nwhile(test condition)<\/p>\n\n\n\n {<\/p>\n\n\n\n body of the loop;<\/p>\n\n\n\n }<\/p>\n<\/div><\/div>\n<\/div><\/div>\n\n\n\n Q.Write a program to print your name five times using while loop.<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i;\t\ni=1;\nwhile(i<=5)\n{\ncout<<\u201d\\n AIPS ACADEMY\u201d;\ni++;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/strong><\/p>\n\n\n\n \nAIPS ACADEMY<\/p>\n\n\n\n AIPS ACADEMY<\/p>\n\n\n\n AIPS ACADEMY<\/p>\n\n\n\n AIPS ACADEMY<\/p>\n\n\n\n AIPS ACADEMY<\/p>\n<\/div><\/div>\n\n\n\n OR<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i;\t\ni=5;\nwhile(i>=1)\n{\ncout<<\u201d\\n AIPS ACADEMY\u201d;\ni--;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/strong><\/p>\n\n\n\n \nAIPS ACADEMY<\/p>\n\n\n\n AIPS ACADEMY<\/p>\n\n\n\n AIPS ACADEMY<\/p>\n\n\n\n AIPS ACADEMY<\/p>\n\n\n\n AIPS ACADEMY<\/p>\n\n\n\n Q.Write a program to print reverse of digits of input number.<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint n,r,s=0;\t\ncout<<\u201dEnter value of n=\u201d;\ncin>>n;\nwhile(n>0)\n{\nr=n%10;\ns=s*10+r;\nn=n\/10;\n}\ncout<<\u201dReverse of digits=\u201d<<s;\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/p>\n\n\n\n \nEnter any number=123<\/p>\n\n\n\n Reverse=321<\/p>\n<\/div><\/div>\n\n\n\n Q.Write a program to print sum of digits of of input number.<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint n,r,s=0;\t\ncout<<\u201dEnter value of n=\u201d;\ncin>>n;\nwhile(n>0)\n{\nr=n%10;\ns=s+r;\nn=n\/10;\n}\ncout<<\u201dsum of digits=\u201d<<s;\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/p>\n\n\n\n \nEnter any number=123<\/p>\n\n\n\n \nsum of digits =6<\/p>\n<\/div><\/div>\n<\/div><\/div>\n\n\n\n Q.Write a program to print multiplication of digits of of input number.<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint n,r,s=1;\t\ncout<<\u201dEnter value of n=\u201d;\ncin>>n;\nwhile(n>0)\n{\nr=n%10;\ns=s*r;\nn=n\/10;\n}\ncout<<\u201dMultiplication of digits=\u201d<<s;\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/p>\n\n\n\n Enter any number=423<\/p>\n\n\n\n \nMultiplication of digits =24<\/p>\n<\/div><\/div>\n\n\n\n Q.Write a program to check to number is palindrome or not.<\/p> (palindrome means same number and reverse)<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint n,r,s=0,t;\t\ncout<<\u201dEnter value of n=\u201d;\ncin>>n;\nt=n;\nwhile(n>0)\n{\nr=n%10;\ns=s*10+r;\nn=n\/10;\n}\nif(s==t)\ncout<<\u201dPalindrome number\u201d;\nelse\ncout<<\u201dNot palindrome number\u201d;\ngetch();\n}\n<\/code><\/pre>\n<\/div><\/div>\n\n\n\n\nOutput<\/p>\n\n\n\n \nEnter any number=121<\/p>\n\n\n\n Palindrome number<\/p>\n<\/div><\/div>\n\n\n\n <\/p>\n\n\n\n <\/p>\n\n\n\n Do- while loop:-<\/strong><\/h3>\n\n\n\nThis loop executes its body at least once whether the specified condition is true or false.<\/p>\n\n\n\n This loop executes its body first then checks the test condition.<\/p>\n<\/div><\/div>\n\n\n\n Syntax:<\/p>\n\n\n\n \n\ndo<\/p>\n\n\n\n {<\/p>\n\n\n\n body of the loop;<\/p>\n\n\n\n }while(test condition);<\/p>\n<\/div><\/div>\n\n\n\n <\/p>\n<\/div><\/div>\n\n\n\n Q. Write a program to print your name five times using do while loop.<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i;\t\ni=1;\ndo\n{\ncout<<\u201d\\n AIPS ACADEMY\u201d;\ni++;\n} while(i<=5);\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/p>\n\n\n\n AIPS ACADEMY<\/p>\n\n\n\n AIPS ACADEMY<\/p>\n\n\n\n AIPS ACADEMY<\/p>\n\n\n\n AIPS ACADEMY<\/p>\n\n\n\n AIPS ACADEMY<\/p>\n\n\n\n OR<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i;\t\ni=5;\ndo\n{\ncout<<\u201d\\n AIPS ACADEMY\u201d;\ni--;\n} while(i>=1);\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/strong><\/p>\n\n\n\n AIPS ACADEMY<\/p>\n\n\n\n AIPS ACADEMY<\/p>\n\n\n\n AIPS ACADEMY<\/p>\n\n\n\n AIPS ACADEMY<\/p>\n\n\n\n AIPS ACADEMY<\/p>\n\n\n\n Q.Write a program to print numbers from 1 to 5 using do while.<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i;\t\ni=1;\ndo\n{\ncout<<\u201d\\n\u201d<<i;\ni++;\n} while(i<=5);\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/strong><\/p>\n\n\n\n 1<\/p>\n\n\n\n 2<\/p>\n\n\n\n 3<\/p>\n\n\n\n 4<\/p>\n\n\n\n 5<\/p>\n\n\n\n Q.Write a program to print numbers from 5 to 1 using do while.<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i;\t\ni=5;\ndo\n{\ncout<<\u201d\\n\u201d<<i;\ni--;\n} while(i>=1);\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\nOutput<\/strong><\/p>\n\n\n\n 5<\/p>\n\n\n\n 4<\/p>\n\n\n\n 3<\/p>\n\n\n\n 2<\/p>\n\n\n\n 1<\/p>\n\n\n\n Nested Loop in C++<\/h2>\n\n\n\none loop inside another loop is called nested loop. It is used to print data in tabular form.<\/p>\n\n\n\n example:<\/p>\n\n\n\n \nfor(i=1;i<=3;i++)<\/p>\n\n\n\n {<\/p>\n\n\n\n for(j=1;j<=3;j++)<\/p>\n\n\n\n {<\/p>\n\n\n\n cout<<“AIPS \\t”;<\/p>\n\n\n\n }<\/p>\n\n\n\n cout<<“\\n”;<\/p>\n\n\n\n }<\/p>\n<\/div><\/div>\n\n\n\n here j is nested or inner loop and i is outer loop.<\/p>\n\n\n\n outer loop for row and inner loop for column<\/strong><\/p>\n\n\n\n <\/p>\n\n\n\n Q.Write a program to print following format.<\/p> AIPS AIPS AIPS AIPS<\/p> AIPS AIPS AIPS AIPS <\/p> AIPS AIPS AIPS AIPS<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i,j;\nfor(i=1;i<=3;i++)\n{\nfor(j=1;j<=4;j++)\n{\ncout<<\u201dAIPS \\t\u201d;\n}\ncout<<\u201d\\n\u201d;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n<\/p>\n\n\n\n Q.Write a program to print following format.<\/p> 1 2 3 4 5<\/p> 1 2 3 4 5<\/p> 1 2 3 4 5<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i,j;\nfor(i=1;i<=3;i++)\n{\nfor(j=1;j<=5;j++)\n{\ncout<<j<<\u201d\\t\u201d;\n}\ncout<<\u201d\\n\u201d;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\nQ.Write a program to print following format.<\/p> 1 1 1 1 1<\/p> 2 2 2 2 2 <\/p> 3 3 3 3 3 <\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i,j;\nfor(i=1;i<=3;i++)\n{\nfor(j=1;j<=5;j++)\n{\ncout<<i<<\u201d\\t\u201d;\n}\ncout<<\u201d\\n\u201d;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\nQ.Write a program to print following format.<\/p> AIPS <\/p> AIPS AIPS <\/p> AIPS AIPS AIPS <\/p> AIPS AIPS AIPS AIPS <\/p> <\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i,j;\nfor(i=1;i<=4;i++)\n{\nfor(j=1;j<=i;j++)\n{\ncout<<\u201dAIPS \\t\u201d;\n}\ncout<<\u201d\\n\u201d;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\nQ.Write a program to print following format.<\/p> 1 <\/p> 1 2 <\/p> 1 2 3 <\/p>1 2 3 4<\/strong> <\/cite><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i,j;\nfor(i=1;i<=4;i++)\n{\nfor(j=1;j<=i;j++)\n{\ncout<<j<<\u201d \\t\u201d;\n}\ncout<<\u201d\\n\u201d;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\nQ.Write a program to print following format.<\/p> 1<\/p> 2 2 <\/p> 3 3 3 <\/p> 4 4 4 4<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i,j;\nfor(i=1;i<=4;i++)\n{\nfor(j=1;j<=i;j++)\n{\ncout<<i<<\u201d \\t\u201d;\n}\ncout<<\u201d\\n\u201d;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\nQ.Write a program to print following format.<\/p> A B C D E<\/p> A B C D E<\/p> A B C D E<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i,j;\nfor(i=65;i<=67;i++)\n{\nfor(j=65;j<=69;j++)\n{\ncout<<(char)j<<\u201d \\t\u201d;\n}\ncout<<\u201d\\n\u201d;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\nQ.Write a program to print following format.<\/p> A A A A A<\/p> B B B B B <\/p> C C C C C<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i,j;\nfor(i=65;i<=67;i++)\n{\nfor(j=65;j<=69;j++)\n{\ncout<<(char)i<<\u201d \\t\u201d;\n}\ncout<<\u201d\\n\u201d;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\nQ.Write a program to print following format.<\/p> A <\/p> A B <\/p> A B C <\/p> A B C D<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i,j;\nfor(i=65;i<=68;i++)\n{\nfor(j=65;j<=i;j++)\n{\ncout<<(char)j<<\u201d \\t\u201d;\n}\ncout<<\u201d\\n\u201d;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\nQ.Write a program to print following format.<\/p> A<\/p> B B<\/p> C C C<\/p> D D D D<\/p><\/blockquote>\n\n\n\n #include<iostream.h>\n#include<conio.h>\nvoid main() \n{\nclrscr();\nint i,j;\nfor(i=65;i<=68;i++)\n{\nfor(j=65;j<=i;j++)\n{\ncout<<(char)i<<\u201d \\t\u201d;\n}\ncout<<\u201d\\n\u201d;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n<\/p>\n\n\n\n \n<\/iframe>\n<\/div><\/figure>\n\n\n\nto be continued…<\/strong> <\/p>\n\n\n\n<\/p>\n\n\n\n<\/p>\n\n\n\n<\/p>\n","protected":false},"excerpt":{"rendered":"Loops are used to repeat set of statement as long as specified condition is true. loop\/Iteration is a block of statement which are repeatedly executed for a certain number of times. Loop is used to execute the statements repeatedly as long as the specified condition is true. There are two categories of Loops: Entry control […]<\/p>\n","protected":false},"author":1,"featured_media":337,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[4,5,7,6],"tags":[],"class_list":["post-334","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-11th-computer-science","category-12th-computer-science","category-cbse","category-jac"],"_links":{"self":[{"href":"https:\/\/aipsacademy.com\/blogs\/wp-json\/wp\/v2\/posts\/334","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/aipsacademy.com\/blogs\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/aipsacademy.com\/blogs\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/aipsacademy.com\/blogs\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/aipsacademy.com\/blogs\/wp-json\/wp\/v2\/comments?post=334"}],"version-history":[{"count":8,"href":"https:\/\/aipsacademy.com\/blogs\/wp-json\/wp\/v2\/posts\/334\/revisions"}],"predecessor-version":[{"id":569,"href":"https:\/\/aipsacademy.com\/blogs\/wp-json\/wp\/v2\/posts\/334\/revisions\/569"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/aipsacademy.com\/blogs\/wp-json\/wp\/v2\/media\/337"}],"wp:attachment":[{"href":"https:\/\/aipsacademy.com\/blogs\/wp-json\/wp\/v2\/media?parent=334"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/aipsacademy.com\/blogs\/wp-json\/wp\/v2\/categories?post=334"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/aipsacademy.com\/blogs\/wp-json\/wp\/v2\/tags?post=334"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}