{"id":334,"date":"2023-01-19T13:33:00","date_gmt":"2023-01-19T13:33:00","guid":{"rendered":"https:\/\/aipsacademy.com\/blogs\/?p=334"},"modified":"2023-07-09T01:50:29","modified_gmt":"2023-07-09T01:50:29","slug":"loops-iteration-statement-in-c-language","status":"publish","type":"post","link":"https:\/\/aipsacademy.com\/blogs\/2023\/01\/19\/loops-iteration-statement-in-c-language\/","title":{"rendered":"Loops \/ Iteration statement in C++ Language"},"content":{"rendered":"\n

Loops are used to repeat set of statement as long as specified condition is true.<\/p>\n\n\n\n

loop\/Iteration is a block of statement<\/a> which are repeatedly executed for a certain number of times.<\/p>\n\n\n\n

Loop is used to execute the statements<\/a> repeatedly as long as the specified condition is true.<\/p>\n\n\n\n

\n

There are two categories of Loops:<\/p>\n\n\n\n

  1. Entry control loop<\/a>:- This loop executes when specified condition is true. Example for loop, while loop.<\/li>
  2. Exit control loop:- This loop executes at least once whether the specified condition is true or false. example do while loop.<\/li><\/ol>\n<\/div><\/div>\n\n\n\n

    Parts of Loop<\/em><\/strong><\/p>\n\n\n\n

    \n

    There are following parts of loop.<\/p>\n\n\n\n

    Initialization :- It indicates from where loop is to be started.<\/strong><\/p>\n\n\n\n

    example: i=1;<\/p>\n\n\n\n

    Test condition:- It indicates how many times loop is to be executed.<\/strong><\/p>\n\n\n\n

    example: i<=5;<\/p>\n\n\n\n

    Increment \/Decrement<\/a> :- To reach an end of the test condition increment or decremen<\/a>t is needed.<\/strong><\/p>\n\n\n\n

    example: i++, i- –<\/p>\n<\/div><\/div>\n\n\n\n

    For Loop:<\/strong>–<\/p>\n\n\n\n

    This loop is the easiest loop among all the loops because it contains all the loop control structure at one place in a pair of parenthesis.<\/p>\n\n\n\n

    It is used for fixed time iteration.<\/p>\n\n\n\n

    It checks the initialization first then evaluates the test condition and if test condition becomes true then body of the loop is executed.<\/p>\n\n\n\n

    At last control goes to increment\\ decrement and again test condition is evaluated , if test condition founds true then again body of the loop is executed. <\/p>\n\n\n\n

    This process continues until the specified condition is true.<\/p>\n\n\n\n

    syntax:<\/p>\n\n\n\n

    for(initialization; test condition ; increment\/decrement)<\/p>\n\n\n\n

    {<\/p>\n\n\n\n

    body of the loop;<\/p>\n\n\n\n

    }<\/p>\n\n\n\n

    Q.Write a program to print your name five times using for loop.<\/p><\/blockquote>\n\n\n\n

    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i;\t\nfor(i=1;i<=5;i++)\n{\ncout<<\"\\n AIPS ACADEMY\";\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/strong><\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    OR <\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i;\t\nfor(i=5;i>=1;i--)\n{\ncout<<\"\\n AIPS ACADEMY\";\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    Q.Write a program to print numbers from 1 to 5.<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i;\t\nfor(i=1;i<=5;i++)\n{\ncout<<\u201d\\n\u201d<<i;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    output<\/strong><\/p>\n\n\n\n
    \n
    1<\/p>\n\n\n\n
    2<\/p>\n\n\n\n
    3<\/p>\n\n\n\n
    4<\/p>\n\n\n\n
    5<\/p>\n<\/div><\/div>\n\n\n\n
    Q. Write a program to print number from 5 to 1.<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i;\t\nfor(i=5;i>=1;i- -)\n{\ncout<<\u201d\\n\u201d<<i;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/p>\n\n\n\n
    5<\/p>\n\n\n\n
    4<\/p>\n\n\n\n
    3<\/p>\n\n\n\n
    2<\/p>\n\n\n\n
    1<\/p>\n\n\n\n
    Q. Write a program to print even number from 1 to 20.<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i;\t\nfor(i=2;i<=20;i+=2)\n{\ncout<<\u201d\\n\u201d<<i;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/strong><\/p>\n\n\n\n
    \n
    2<\/p>\n\n\n\n
    4<\/p>\n\n\n\n
    6<\/p>\n\n\n\n
    8<\/p>\n\n\n\n
    10<\/p>\n\n\n\n
    12<\/p>\n\n\n\n
    14<\/p>\n\n\n\n
    16<\/p>\n\n\n\n
    18<\/p>\n\n\n\n
    20<\/p>\n\n\n\n
    <\/p>\n<\/div><\/div>\n\n\n\n
    Q. Write a program to print odd number from 1 to 10.<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i;\t\nfor(i=1;i<=10;i+=2)\n{\ncout<<\u201d\\n\u201d<<i;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/strong><\/p>\n\n\n\n
    \n
    \n
    1<\/p>\n\n\n\n
    3<\/p>\n\n\n\n
    5<\/p>\n\n\n\n
    7<\/p>\n\n\n\n
    9<\/p>\n<\/div><\/div>\n<\/div><\/div>\n\n\n\n
    Q. Find output.<\/strong><\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i;\t\nfor(i=5;i<=50;i+=5)\n{\ncout<<\u201d\\n\u201d<<i;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/p>\n\n\n\n
    \n
    \n
    5<\/p>\n\n\n\n
    10<\/p>\n\n\n\n
    15<\/p>\n\n\n\n
    20<\/p>\n\n\n\n
    25<\/p>\n\n\n\n
    30<\/p>\n\n\n\n
    35<\/p>\n\n\n\n
    40<\/p>\n\n\n\n
    45<\/p>\n\n\n\n
    50<\/p>\n<\/div><\/div>\n\n\n\n
    <\/p>\n<\/div><\/div>\n\n\n\n
    Q.Find output<\/strong><\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i;\t\nfor(i=50;i>=5;i-=5)\n{\ncout<<\u201d\\n\u201d<<i;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/strong><\/p>\n\n\n\n
    \n
    50<\/p>\n\n\n\n
    45<\/p>\n\n\n\n
    40<\/p>\n\n\n\n
    35<\/p>\n\n\n\n
    30<\/p>\n\n\n\n
    25<\/p>\n\n\n\n
    20<\/p>\n\n\n\n
    15<\/p>\n\n\n\n
    10<\/p>\n\n\n\n
    5<\/p>\n<\/div><\/div>\n\n\n\n
    Q.Write a program to print your name up to specified term.<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint n,i;\t\ncout<<\u201dEnter terms\u201d;\ncin>>n;\nfor(i=1;i<=n;i++)\n{\ncout<<\u201d\\n AIPS ACADEMY\u201d;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/strong><\/p>\n\n\n\n
    \n
    Enter terms=4<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    Q.Write a program to print numbers from 1 to specified term<\/p><\/blockquote>\n<\/div><\/div>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint n,i;\t\ncout<<\u201dEnter terms\u201d;\ncin>>n;\nfor(i=1;i<=n;i++)\n{\ncout<<\u201d\\n\u201d<<i;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/strong><\/p>\n\n\n\n
    \n
    Enter terms=5<\/p>\n\n\n\n
    1<\/p>\n\n\n\n
    2<\/p>\n\n\n\n
    3<\/p>\n\n\n\n
    4<\/p>\n\n\n\n
    5<\/p>\n<\/div><\/div>\n\n\n\n
    Q.Write a program to print numbers from specified term to 1.<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint n,i;\t\ncout<<\u201dEnter terms\u201d;\ncin>>n;\nfor(i=n;i>=1;i--)\n{\ncout<<\u201d\\n\u201d<<i;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/strong><\/p>\n\n\n\n
    \n
    Enter terms=5<\/p>\n\n\n\n
    5<\/p>\n\n\n\n
    4<\/p>\n\n\n\n
    3<\/p>\n\n\n\n
    2<\/p>\n\n\n\n
    1<\/p>\n\n\n\n
    Q.Write a program to print table of input number.<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint n,i,j;\t\ncout<<\u201dEnter any number=\u201d;\ncin>>n;\nfor(i=1;i<=10;i++)\n{\nj=n*i;\ncout<<\u201d\\n\u201d<<j;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/strong><\/p>\n\n\n\n
    \n
    Enter any number =5<\/p>\n\n\n\n
    5<\/p>\n\n\n\n
    10<\/p>\n\n\n\n
    15<\/p>\n\n\n\n
    20<\/p>\n\n\n\n
    25<\/p>\n\n\n\n
    30<\/p>\n\n\n\n
    35<\/p>\n\n\n\n
    40<\/p>\n\n\n\n
    45<\/p>\n\n\n\n
    50<\/p>\n\n\n\n
    Q.Write a program to print table of input number in following format.<\/p>
    Enter any number=5<\/p>
    5*1=5<\/p>
    5*2=10<\/p>
    …………..<\/p>
    ……………<\/p>
    5*10=50<\/p><\/blockquote>\n<\/div><\/div>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint n,i,j;\t\ncout<<\u201dEnter any number=\u201d;\ncin>>n;\nfor(i=1;i<=10;i++)\n{\nj=n*i;\ncout<<\u201d\\n\u201d<<n<<\u201d*\u201d<<i<<\u201d=\u201d<<j;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/strong><\/p>\n\n\n\n
    \n
    Enter any number=5<\/p>\n\n\n\n
    5*1=5<\/p>\n\n\n\n
    5*2=10<\/p>\n\n\n\n
    …………..<\/p>\n\n\n\n
    ……………<\/p>\n\n\n\n
    5*10=50<\/p>\n\n\n\n
    Q.Write a program to print Factorial of input number.<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint n,i,j=1;\t\ncout<<\u201dEnter any number=\u201d;\ncin>>n;\nfor(i=n;i>=1;i--)\n{\nj=j*i;\n}\ncout<<\u201dFactorial=\u201d<<j;\ngetch();\n}\n<\/code><\/pre>\n<\/div><\/div>\n<\/div><\/div>\n\n\n\n
    Output<\/strong><\/p>\n\n\n\n
    \n
    Enter any number=5<\/p>\n\n\n\n
    Factorial=120<\/p>\n<\/div><\/div>\n\n\n\n
    OR<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint n,i,j=1;\t\ncout<<\u201dEnter any number=\u201d;\ncin>>n;\nfor(i=n;i>=1;i--)\n{\nj=j*i;\ncout<<i<<\u201d*\u201d;\n}\ncout<<\u201d=\u201d<<j;\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/p>\n\n\n\n
    \n
    Enter any number=5<\/p>\n\n\n\n
    5*4*3*2*1*=120<\/p>\n<\/div><\/div>\n\n\n\n
    Q.Write a program to find factor of input number.<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint n,i;\t\ncout<<\u201dEnter any number=\u201d;\ncin>>n;\nfor(i=1;i<=n;i++)\n{\nif(n%i==0)\n{\ncout<<\u201d\\n\u201d<<i;\n}\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/p>\n\n\n\n
    \n
    Enter any number =6<\/p>\n\n\n\n
    1<\/p>\n\n\n\n
    2<\/p>\n\n\n\n
    3<\/p>\n\n\n\n
    6<\/p>\n<\/div><\/div>\n\n\n\n
    Q.Write a program to find sum of factors of input number.<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint n,i,s=0;\t\ncout<<\u201dEnter any number=\u201d;\ncin>>n;\nfor(i=1;i<=n;i++)\n{\nif(n%i==0)\n{\ncout<<\u201d\\n\u201d<<i;\ns=s+i;\n}\n}\ncout<<\u201dsum of factor=\u201d<<s;\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/strong><\/p>\n\n\n\n
    \n
    \n
    Enter any number =6<\/p>\n\n\n\n
    1<\/p>\n\n\n\n
    2<\/p>\n\n\n\n
    3<\/p>\n\n\n\n
    6<\/p>\n<\/div><\/div>\n\n\n\n
    sum of factors=12<\/p>\n<\/div><\/div>\n\n\n\n
    Q.Write a program to check number is perfect or not.<\/p>
    (sum of factors =two times of number)<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint n,i,s=0;\t\ncout<<\u201dEnter any number=\u201d;\ncin>>n;\nfor(i=1;i<=n;i++)\n{\nif(n%i==0)\n{\ns=s+i;\n}\n}\nif(s==n*2)\ncout<<\u201dPerfect number\u201d;\nelse\ncout<<\u201dNot perfect number\u201d;\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/strong><\/p>\n\n\n\n
    \n
    Enter any number=6<\/p>\n\n\n\n
    Perfect number<\/p>\n\n\n\n
    Q.Find output.<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i;\t\nfor(i=65;i<=90;i++)\n{\ncout<<i <<\"\\t\";\n}\n\ngetch();\n}\n<\/code><\/pre>\n<\/div><\/div>\n\n\n\n
    Output<\/strong><\/p>\n\n\n\n
    65 66 67 68 69 70 ……..90<\/p>\n\n\n\n
    Q.Write a program to print uppercase alphabet using ASCII Code.<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i;\t\nfor(i=65;i<=90;i++)\n{\ncout<<(char)i;\n}\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/strong><\/p>\n\n\n\n
    A B C D E F G H……….Z<\/p>\n\n\n\n
    Q.Write a program to print uppercase alphabet in reverse order.<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i;\t\nfor(i=90;i>=65;i--)\n{\ncout<<(char)i;\n}\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output <\/p>\n\n\n\n
    Z Y X W ………………..A<\/p>\n\n\n\n
    Q. Find Output<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i;\t\nfor(i=90;i>=65;i--)\n{\ncout<<i;\n}\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    90 89 88 87…..65<\/p>\n\n\n\n
    Q.Write a program to print lowercase alphabet using ASCII Code.<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i;\t\nfor(i=97;i<=122;i++)\n{\ncout<<(char)i;\n}\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/p>\n\n\n\n
    a b c d e …………………..z<\/p>\n\n\n\n
    Q.Find output<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i;\t\nfor(i=97;i<=122;i++)\n{\ncout<<i;\n}\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/p>\n\n\n\n
    97 98 99 100…….122<\/p>\n\n\n\n
    Q.Write a program to print lowercase alphabet in reverse order.<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i;\t\nfor(i=122;i>=97;i--)\n{\ncout<<(char)i;\n}\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/p>\n\n\n\n
    z y x w ………………..a<\/p>\n\n\n\n
    Q.Write a program to print numbers from 0 to 9 using ASCII code.<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i;\t\nfor(i=48;i<=57;i++)\n{\ncout<<(char)i;\n}\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/p>\n\n\n\n
    0 1 2 3 4 5 6………………..9<\/p>\n\n\n\n
    Q.Find output.<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i;\t\nfor(i=48;i<=57;i++)\n{\ncout<<i;\n}\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/p>\n\n\n\n
    48 49 50 51 52 53 ……..57<\/p>\n\n\n\n
    Q.Write a program to print following series. <\/p>
    1 2 3 4 5 ……………n<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint n,i;\t\ncout<<\u201dEnter value of n=\u201d;\ncin>>n;\nfor(i=1;i<=n;i++)\n{\ncout<<i<<\u201d\\t\u201d;\n}\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output <\/p>\n\n\n\n
    Enter value of  n=5<\/p>\n\n\n\n
    1 2 3 4 5 <\/p>\n\n\n\n
    Q.Write a program to print following series and sum also.<\/p>
    1 2 3 4 5 ……………n<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint n,i,s=0;\t\ncout<<\u201dEnter value of n=\u201d;\ncin>>n;\nfor(i=1;i<=n;i++)\n{\ncout<<i<<\u201d\\t\u201d;\ns=s+i;\n}\ncout<<\u201d\\nsum of series=\u201d<<s;\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output <\/p>\n\n\n\n
    Enter value of  n=5<\/p>\n\n\n\n
    1 2 3 4 5 <\/p>\n\n\n\n
    sum of series=15<\/p>\n\n\n\n
    While loop:-<\/strong><\/h3>\n\n\n\n
    This loop is an entry control loop. It executes the block of statement as long as the certain condition is satisfied.<\/p>\n\n\n\n
    Control exits from loop when the specified condition is false.<\/p>\n\n\n\n
    Syntax:<\/p>\n\n\n\n
    \n
    \n
    while(test condition)<\/p>\n\n\n\n
    {<\/p>\n\n\n\n
    body of the loop;<\/p>\n\n\n\n
    }<\/p>\n<\/div><\/div>\n<\/div><\/div>\n\n\n\n
    Q.Write a program to print your name five times using while loop.<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i;\t\ni=1;\nwhile(i<=5)\n{\ncout<<\u201d\\n AIPS ACADEMY\u201d;\ni++;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/strong><\/p>\n\n\n\n
    \n
    AIPS ACADEMY<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n<\/div><\/div>\n\n\n\n
    OR<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i;\t\ni=5;\nwhile(i>=1)\n{\ncout<<\u201d\\n AIPS ACADEMY\u201d;\ni--;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/strong><\/p>\n\n\n\n
    \n
    AIPS ACADEMY<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    Q.Write a program to print reverse of digits of input number.<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint n,r,s=0;\t\ncout<<\u201dEnter value of n=\u201d;\ncin>>n;\nwhile(n>0)\n{\nr=n%10;\ns=s*10+r;\nn=n\/10;\n}\ncout<<\u201dReverse of digits=\u201d<<s;\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/p>\n\n\n\n
    \n
    Enter any number=123<\/p>\n\n\n\n
    Reverse=321<\/p>\n<\/div><\/div>\n\n\n\n
    Q.Write a program to print sum of digits of of input number.<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint n,r,s=0;\t\ncout<<\u201dEnter value of n=\u201d;\ncin>>n;\nwhile(n>0)\n{\nr=n%10;\ns=s+r;\nn=n\/10;\n}\ncout<<\u201dsum of digits=\u201d<<s;\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/p>\n\n\n\n
    \n
    Enter any number=123<\/p>\n\n\n\n
    \n
    sum of digits =6<\/p>\n<\/div><\/div>\n<\/div><\/div>\n\n\n\n
    Q.Write a program to print multiplication of digits of of input number.<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint n,r,s=1;\t\ncout<<\u201dEnter value of n=\u201d;\ncin>>n;\nwhile(n>0)\n{\nr=n%10;\ns=s*r;\nn=n\/10;\n}\ncout<<\u201dMultiplication of digits=\u201d<<s;\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/p>\n\n\n\n
    Enter any number=423<\/p>\n\n\n\n
    \n
    Multiplication of digits =24<\/p>\n<\/div><\/div>\n\n\n\n
    Q.Write a program to check to number is palindrome or not.<\/p>
    (palindrome means same number and reverse)<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint n,r,s=0,t;\t\ncout<<\u201dEnter value of n=\u201d;\ncin>>n;\nt=n;\nwhile(n>0)\n{\nr=n%10;\ns=s*10+r;\nn=n\/10;\n}\nif(s==t)\ncout<<\u201dPalindrome number\u201d;\nelse\ncout<<\u201dNot palindrome number\u201d;\ngetch();\n}\n<\/code><\/pre>\n<\/div><\/div>\n\n\n\n
    \n
    Output<\/p>\n\n\n\n
    \n
    Enter any number=121<\/p>\n\n\n\n
    Palindrome number<\/p>\n<\/div><\/div>\n\n\n\n
    <\/p>\n\n\n\n
    <\/p>\n\n\n\n
    Do- while loop:-<\/strong><\/h3>\n\n\n\n
    This loop executes its body at least once whether the specified condition is true or false.<\/p>\n\n\n\n
    This loop executes its body first then checks the test condition.<\/p>\n<\/div><\/div>\n\n\n\n
    Syntax:<\/p>\n\n\n\n
    \n
    \n
    do<\/p>\n\n\n\n
    {<\/p>\n\n\n\n
    body of the loop;<\/p>\n\n\n\n
    }while(test condition);<\/p>\n<\/div><\/div>\n\n\n\n
    <\/p>\n<\/div><\/div>\n\n\n\n
    Q. Write a program to print your name five times using do while loop.<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i;\t\ni=1;\ndo\n{\ncout<<\u201d\\n AIPS ACADEMY\u201d;\ni++;\n} while(i<=5);\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    OR<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i;\t\ni=5;\ndo\n{\ncout<<\u201d\\n AIPS ACADEMY\u201d;\ni--;\n} while(i>=1);\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/strong><\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    AIPS ACADEMY<\/p>\n\n\n\n
    Q.Write a program to print numbers from 1 to 5 using do while.<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i;\t\ni=1;\ndo\n{\ncout<<\u201d\\n\u201d<<i;\ni++;\n} while(i<=5);\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/strong><\/p>\n\n\n\n
    1<\/p>\n\n\n\n
    2<\/p>\n\n\n\n
    3<\/p>\n\n\n\n
    4<\/p>\n\n\n\n
    5<\/p>\n\n\n\n
    Q.Write a program to print numbers from 5 to 1 using do while.<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i;\t\ni=5;\ndo\n{\ncout<<\u201d\\n\u201d<<i;\ni--;\n} while(i>=1);\n\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Output<\/strong><\/p>\n\n\n\n
    5<\/p>\n\n\n\n
    4<\/p>\n\n\n\n
    3<\/p>\n\n\n\n
    2<\/p>\n\n\n\n
    1<\/p>\n\n\n\n
    Nested Loop in C++<\/h2>\n\n\n\n
    one loop inside another loop is called nested loop. It is used to print data in tabular form.<\/p>\n\n\n\n
    example:<\/p>\n\n\n\n
    \n
    for(i=1;i<=3;i++)<\/p>\n\n\n\n
    {<\/p>\n\n\n\n
    for(j=1;j<=3;j++)<\/p>\n\n\n\n
    {<\/p>\n\n\n\n
    cout<<“AIPS \\t”;<\/p>\n\n\n\n
    }<\/p>\n\n\n\n
    cout<<“\\n”;<\/p>\n\n\n\n
    }<\/p>\n<\/div><\/div>\n\n\n\n
    here j is nested or inner loop and i is outer loop.<\/p>\n\n\n\n
    outer loop for row and inner loop for column<\/strong><\/p>\n\n\n\n
    <\/p>\n\n\n\n
    Q.Write a program to print following format.<\/p>
    AIPS AIPS AIPS AIPS<\/p>
    AIPS AIPS AIPS AIPS <\/p>
    AIPS AIPS AIPS AIPS<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i,j;\nfor(i=1;i<=3;i++)\n{\nfor(j=1;j<=4;j++)\n{\ncout<<\u201dAIPS  \\t\u201d;\n}\ncout<<\u201d\\n\u201d;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    <\/p>\n\n\n\n
    Q.Write a program to print following format.<\/p>
    1 2 3 4 5<\/p>
    1 2 3 4 5<\/p>
    1 2 3 4 5<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i,j;\nfor(i=1;i<=3;i++)\n{\nfor(j=1;j<=5;j++)\n{\ncout<<j<<\u201d\\t\u201d;\n}\ncout<<\u201d\\n\u201d;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Q.Write a program to print following format.<\/p>
    1 1 1 1 1<\/p>
    2 2 2 2 2 <\/p>
    3 3 3 3 3 <\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i,j;\nfor(i=1;i<=3;i++)\n{\nfor(j=1;j<=5;j++)\n{\ncout<<i<<\u201d\\t\u201d;\n}\ncout<<\u201d\\n\u201d;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Q.Write a program to print following format.<\/p>
    AIPS <\/p>
    AIPS AIPS <\/p>
    AIPS AIPS AIPS <\/p>
    AIPS AIPS AIPS AIPS <\/p>
    <\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i,j;\nfor(i=1;i<=4;i++)\n{\nfor(j=1;j<=i;j++)\n{\ncout<<\u201dAIPS \\t\u201d;\n}\ncout<<\u201d\\n\u201d;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Q.Write a program to print following format.<\/p>
    1 <\/p>
    1 2 <\/p>
    1 2 3 <\/p>1 2 3 4<\/strong>
    <\/cite><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i,j;\nfor(i=1;i<=4;i++)\n{\nfor(j=1;j<=i;j++)\n{\ncout<<j<<\u201d \\t\u201d;\n}\ncout<<\u201d\\n\u201d;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Q.Write a program to print following format.<\/p>
    1<\/p>
    2 2 <\/p>
    3 3 3 <\/p>
    4 4 4 4<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i,j;\nfor(i=1;i<=4;i++)\n{\nfor(j=1;j<=i;j++)\n{\ncout<<i<<\u201d \\t\u201d;\n}\ncout<<\u201d\\n\u201d;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Q.Write a program to print following format.<\/p>
    A B C D E<\/p>
    A B C D E<\/p>
    A B C D E<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i,j;\nfor(i=65;i<=67;i++)\n{\nfor(j=65;j<=69;j++)\n{\ncout<<(char)j<<\u201d \\t\u201d;\n}\ncout<<\u201d\\n\u201d;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Q.Write a program to print following format.<\/p>
    A A A A A<\/p>
    B B B B B <\/p>
    C C C C C<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i,j;\nfor(i=65;i<=67;i++)\n{\nfor(j=65;j<=69;j++)\n{\ncout<<(char)i<<\u201d \\t\u201d;\n}\ncout<<\u201d\\n\u201d;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Q.Write a program to print following format.<\/p>
    A <\/p>
    A B <\/p>
    A B C <\/p>
    A B C D<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i,j;\nfor(i=65;i<=68;i++)\n{\nfor(j=65;j<=i;j++)\n{\ncout<<(char)j<<\u201d \\t\u201d;\n}\ncout<<\u201d\\n\u201d;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    Q.Write a program to print following format.<\/p>
    A<\/p>
    B B<\/p>
    C C C<\/p>
    D D D D<\/p><\/blockquote>\n\n\n\n
    #include<iostream.h>\n#include<conio.h>\nvoid main()  \n{\nclrscr();\nint i,j;\nfor(i=65;i<=68;i++)\n{\nfor(j=65;j<=i;j++)\n{\ncout<<(char)i<<\u201d \\t\u201d;\n}\ncout<<\u201d\\n\u201d;\n}\ngetch();\n}\n<\/code><\/pre>\n\n\n\n
    <\/p>\n\n\n\n
    \n